I plotted a histogram of the total intensity of the Hartmann sensor when illuminated and found that the 128 count problem extends all the way up through the distribution. This isn't unreasonable since that digitizer is going to be called on mutliple times.
First things first, the value of 128 equals a 1 in the 8th digitizer, so for a 16-bit number in binary, it looks like this: 0000 0000 1000 0000 and in hex-code 080
The values of the peaks in the attached distribution are as follows:
Number of counts |
Hex Code |
128
|
080 |
384 |
180 |
640 |
280 |
896 |
380 |
1152 |
480 |
1408 |
580 |
1664 |
680 |
1920 |
780 |
2176 |
880 |
2432 |
980 |
2688 |
A80 |
2944 |
B80 |
3200 |
C80 |
|