First I was confused, but now I think I understood.
My confusion:
If the k get bigger, L get smaller, C get bigger. This makes R(L) smaller and R(C) smaller. This sounds very nice. But why smaller k is preferable in the Kiwamu's result?
Explanation:
The resultant impedance of the network at a resonance is determined by Zres = L/(R C) or something like that. Here R = R(L)+R(C). (I hope this is right.)
Here larger Zres is preferable. So smaller R is nice.
But If the speed of reduction for R is slower than that of L/C (which is proportional to k^2), increasing k does not help us to increase of Zres. And that's the case.
This means "if we can put the LC network in the box of EOM, we can do better job!" as we can reduce Cp.
Quote: 
Loss for Capacitor : R(C) = 0.5 (C / 10pF)^{0.3} Ohm
Loss for Inductor : R(L) = 0.1 ( L / 1uH) Ohm

